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24x^2-71x+16=0
a = 24; b = -71; c = +16;
Δ = b2-4ac
Δ = -712-4·24·16
Δ = 3505
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-71)-\sqrt{3505}}{2*24}=\frac{71-\sqrt{3505}}{48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-71)+\sqrt{3505}}{2*24}=\frac{71+\sqrt{3505}}{48} $
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